A problem in mathematics is given to 3 students whose chances of solving individually are ½ , ⅓ and ¼. The probability that the problem will be solved at least by one, is what?
The best way to solve this is to first find the probability of them not been able to solve the question individually, then from that find the probability of them not been able to solve the question collectively. From there, you can then find the probability of one of them solving it (which will be 1 - probability of them not solving it).
Probability of them not been able to solve the question individually will be (1 - ½ ), (1 - ⅓) and (1 - ¼) Which are: ½, ⅔ and ¾
Probability of them not been able to solve the question collectively will then be: ½ x ⅔ x ¾ = ⁶⁄₂₄ ⁶⁄₂₄ can be reduced to ¼
The probability of then solving the question collectively will then be 1 - ¼ = ¾
A problem in mathematics is given to 3 students whose chances of solving individually are ½ , ⅓ and ¼. The probability that the problem will be solved at least by one, is what?
The best way to solve this is to first find the probability of them not been able to solve the question individually, then from that find the probability of them not been able to solve the question collectively. From there, you can then find the probability of one of them solving it (which will be 1 - probability of them not solving it).
Probability of them not been able to solve the question individually will be (1 - ½ ), (1 - ⅓) and (1 - ¼) Which are: ½, ⅔ and ¾
Probability of them not been able to solve the question collectively will then be: ½ x ⅔ x ¾ = ⁶⁄₂₄ ⁶⁄₂₄ can be reduced to ¼
The probability of then solving the question collectively will then be 1 - ¼ = ¾
Answer: ¾
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